Question

Find a function $y = f(x)$ satisfying the given differential equation and the prescribed initial condition. $\frac{dy}{dx} = \frac{1}{\sqrt{x + 14}}$, $y(2) = -1$ Find the general solution. y(x) = $2\sqrt{x + 14} + C$ Find the solution to the initial value problem. y(x) = $2\sqrt{x + 14} - 9$

          Find a function $y = f(x)$ satisfying the given differential equation and the prescribed initial condition.
$\frac{dy}{dx} = \frac{1}{\sqrt{x + 14}}$, $y(2) = -1$
Find the general solution.
y(x) = $2\sqrt{x + 14} + C$
Find the solution to the initial value problem.
y(x) = $2\sqrt{x + 14} - 9$

Find a function y = f(x) satisfying the given differential equation and the prescribed initial condition.
(dy)/(dx) = (1)/(√(x + 14)), y(2) = -1
Find the general solution.
y(x) = 2√(x + 14) + C
Find the solution to the initial value problem.
y(x) = 2√(x + 14) - 9

Added by Michele Z.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sutara K

02/07/2022

Step 1

Step 1: The given differential equation is: $$\frac{dy}{dx} = \frac{1}{\sqrt{x+14}}$$ Show more…

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Find a function y = f(x) satisfying the given differential equation and the prescribed initial condition. $$\frac{dy}{dx} = \frac{1}{\sqrt{x+14}}, y(2) = -1$$ Find the general solution. y(x) = 2√x+14 + C Find the solution to the initial value problem. y(x) = 2√x+14 - 9