Question

Find a parametrization of the line in which the planes $x - 4y - 2z = 9$ and $-3x + 6y + 3z = -9$ intersect.\ Find the parametrization of the line. Let $z = -6t$.\ x = \\ y = \\ z = \\ - \infty < t < \infty

          Find a parametrization of the line in which the planes $x - 4y - 2z = 9$ and $-3x + 6y + 3z = -9$ intersect.\
Find the parametrization of the line. Let $z = -6t$.\
x = \\
y = \\
z = \\
- \infty < t < \infty

Find a parametrization of the line in which the planes x - 4y - 2z = 9 and -3x + 6y + 3z = -9 intersect.Find the parametrization of the line. Let z = -6t.x =

y =

z =

- ∞< t < ∞

Added by Nicholas M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Israel Hernandez

06/21/2022

Step 1

Step 1: Find the point of intersection of the two planes by solving the system of equations: x - 4y - 2z = 9 -3x + 6y + 3z = -9 Multiplying the first equation by 3 and the second equation by -1 to eliminate x: 3x - 12y - 6z = 27 3x - 6y - 3z = 9 Subtracting the Show more…

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Find a parametrization of the line in which the planes x-4y-2z=9 and -3x+6y+3z=-9 intersect. Find the parametrization of the line. Let z=-6t. x=◻,y=,z=,-infty Find a parametrization of the line in which the planes x -4y -2z=9 and -3x + 6y +3z=-9 intersect. Find the parametrization of the line.Let z=-6t. =Z=X=x 8<t<8