Question

Find a unit vector perpendicular to plane PQR determined by the points P(2, 1, 1), Q(1, 0, 0) and R(2, 2, 2). 1 — (i + j) ?2 1 — (j - k) ?2 1 — (i - j) ?2 1 — (j + k) ?2 Question 2 Find a parametrization for the line segment beginning at P1 and ending at P2. P1(0, 0, 0) and P2(5, 3, 2) x = -5t, y = -3t, z = -2t x = 5t + 5, y = 3t + 3, z = 2t + 2 x = 5t - 5, y = 3t - 3, z = 2t - 2 x = 5t, y = 3t, z = 2t

          Find a unit vector perpendicular to plane PQR determined by the points P(2, 1, 1), Q(1, 0, 0) and R(2, 2, 2).

1
— (i + j)
?2

1
— (j - k)
?2

1
— (i - j)
?2

1
— (j + k)
?2

Question 2

Find a parametrization for the line segment beginning at P1 and ending at P2.

P1(0, 0, 0) and P2(5, 3, 2)

x = -5t, y = -3t, z = -2t

x = 5t + 5, y = 3t + 3, z = 2t + 2

x = 5t - 5, y = 3t - 3, z = 2t - 2

x = 5t, y = 3t, z = 2t

Find a unit vector perpendicular to plane PQR determined by the points P(2, 1, 1), Q(1, 0, 0) and R(2, 2, 2).

1
— (i + j)
?2

1
— (j - k)
?2

1
— (i - j)
?2

1
— (j + k)
?2

Question 2

Find a parametrization for the line segment beginning at P1 and ending at P2.

P1(0, 0, 0) and P2(5, 3, 2)

x = -5t, y = -3t, z = -2t

x = 5t + 5, y = 3t + 3, z = 2t + 2

x = 5t - 5, y = 3t - 3, z = 2t - 2

x = 5t, y = 3t, z = 2t

Added by Juan Jos- J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Suman Saurav Thakur

05/15/2022

Step 1

We can do this by finding the vectors PQ and PR. ** Show more…

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Find a unit vector perpendicular to plane PQR determined by the points P(2, 1, 1), Q(1, 0, 0), and R(1, 2, 2). Find a parametrization for the line segment beginning at P1 and ending at P2: P1(0, 0, 0) and P2(5, 3, 2)