Question

Find a value of the constant $k$, if possible, at which $\qquad f(x) = \begin{cases} kx^2 & x \le 2 \\ -4x + k & x > 2 \end{cases}$ is continuous everywhere. $k = $ (enter \textquotedblleft none\textquotedblright{} if no value).

          Find a value of the constant $k$, if possible, at which
$\qquad f(x) = \begin{cases} kx^2 & x \le 2 \\ -4x + k & x > 2 \end{cases}$
is continuous everywhere.
$k = $ (enter \textquotedblleft none\textquotedblright{} if no value).

Find a value of the constant k, if possible, at which
f(x) = kx^2 x ≤ 2
-4x + k x > 2
is continuous everywhere.
k = (enter “none” if no value).

Added by Peter G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

10/01/2023

Step 1

Step 1: First, we need to find the value of k that makes the inequality 4x + k > 2 true for all x. Show more…

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Find a value of the constant k, if possible, at which 2f(x) = 4x + k > 2 is continuous everywhere. k = enter none into value

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Question

Find a value of the constant $k$, if possible, at which $\qquad f(x) = \begin{cases} kx^2 & x \le 2 \\ -4x + k & x > 2 \end{cases}$ is continuous everywhere. $k = $ (enter \textquotedblleft none\textquotedblright{} if no value).

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