Question

Find a vector equation and parametric equations for the line. (Use the parameter $t$.) The line through the point $(6, -9, 6)$ and parallel to the vector $\left<1, 3, -\frac{2}{3}\right>$ $r(t) = $ $(x(t), y(t), z(t)) = ()

          Find a vector equation and parametric equations for the line. (Use the parameter $t$.)
The line through the point $(6, -9, 6)$ and parallel to the vector $\left<1, 3, -\frac{2}{3}\right>$
$r(t) = $
$(x(t), y(t), z(t)) = ()

Find a vector equation and parametric equations for the line. (Use the parameter t.)
The line through the point (6, -9, 6) and parallel to the vector <1, 3, -(2)/(3)>
r(t) =
(x(t), y(t), z(t)) = ()

Added by Vicente Y.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zack A

08/30/2023

Step 1

Since the line is parallel to the vector (1,3,-2/3), the direction vector of the line is also (1,3,-2/3). The general form of the vector equation of a line is r(t) = r0 + td, where r0 is a point on the line and d is the direction vector of the line. Given that Show more…

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Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (6,-9,6) and parallel to the vector (1,3,-2/3): r(t) = (x(t), y(t), z(t)) = (◻) Need Help? Find a vector equation and parametric equations for the line. (Use the parameter t.) Operator Functions The line through the point (6,-9,6) and parallel to the vector (1,3,-2/3): Symbols Relations = Sets Vectors (x(t), y(t), z(t)) = Trig Need Help? Master 13 Greek