00:01
Hello friends, in this question we are given with the matrix a which is equal to 3x3 matrix that is 1 2 1 2 4 3 3 6 4.
00:13
So, we can reduce this matrix that is row operation that is r2 minus 2 r1 which implies the new row r2 and r3 which is fracted by 3 times of r1 which is new r3.
00:30
So, we get the row that is 1 2 1 0 0 1 and again 0 0 1.
00:42
So, here r3 is get by r3 minus r2.
00:48
So, which is 1 2 1 0 0 1 0 0 0.
00:56
So, finally, we get the simplified row form.
00:59
So, here the row space which is spanned by 1 comma 2 comma 1 and 0 comma 0 comma 1.
01:18
So, let we can say that a comma b comma c be the vertex which is perpendicular to the row space.
01:36
So, we can write the value that is a plus b plus b plus c which is equal to 0 that is a plus 2b plus c which is equal to 0 here c which is equal to 0 that where you get a which is equal to minus 2b.
01:54
So, we can write the value that is minus 2b comma b comma 0 is vertex which is perpendicular to row space.
02:11
So, we can get the matrix which is transport of a.
02:16
So, 1 2 3 2 4 6 and 1 3 and 4 this is the transpose of the matrix.
02:25
So, we can again which is simplified that is 1 2 3 0 0 0 0 0 1...