00:01
Function is given in terms of x and y as equal to f x y equal to minus 4 x y minus x to the power 4 minus y to the power 4.
00:15
Critical points will be add f dash equal to zero.
00:22
So, differentiating with respect to x or partial differentiation f x x y equal to del y del x minus 4 x y minus x to the power 4 minus y to the power 4.
00:38
So, it will be equal to minus 4 y minus 4 x cube and similarly with respect to y f y x y will be equal to minus 4 x minus 4 y cube.
00:58
So, first for critical points f x equal to zero from here minus 4 y minus 4 x cube equal to zero or x y equal to minus x cube.
01:13
Let's see here we can write it as minus 4 x minus 4 y cube equal to zero or x plus y cube equal to zero.
01:38
We know y equal to minus x cube from equation a.
01:45
So, substituting x minus x to the power 9 or x common and 1 minus x to the power 8 equal to zero.
01:59
So, from here one solution is x equal to zero and we can write a square minus b square equal to a minus b a plus b 1 minus x to the power 4 1 plus x to the power 4 equal to zero.
02:13
Similarly 1 minus x square 1 plus x square 1 plus x to the power 4 equal to zero and further expansion in 1 minus x 1 plus x and 1 plus x square 1 plus x to the power 4 equal to zero...