Question

Find all of the points of discontinuity of the function $u = \begin{cases} \frac{x^3 + y^3}{x + y}, & x + y \neq 0; \\ 3, & x + y = 0, \end{cases}$ point out the removable discontinuities.

          Find all of the points of discontinuity of the function
$u = \begin{cases} \frac{x^3 + y^3}{x + y}, & x + y \neq 0; \\ 3, & x + y = 0, \end{cases}$
point out the removable discontinuities.

Find all of the points of discontinuity of the function
u = (x^3 + y^3)/(x + y), x + y ≠ 0;
3, x + y = 0,
point out the removable discontinuities.

Added by Theresa C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Carson Merrill

08/30/2021

Step 1

Step 1: The function u is defined as u = (x^3 + y^3)/(x + y) when x + y ≠ 0, and u = 3 when x + y = 0. Show more…

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Find all of the points of discontinuity of the function [ u=left{egin{array}{ll} rac{x^{3}+y^{3}}{x+y}, & x+y eq 0 3, & x+y=0, end{array} ight. ] point out the removable discontinuities. Find all of the points of discontinuity of the function r+y x+y=0, point out the removable discontinuities.