Question

7. Find all points on the graph of $y = - \left(\frac{1}{3}\right)x^3 + \left(\frac{1}{2}\right)x^2$ where the tangent line has slope 0.

Name: 7. Find all points on the graph of y = - ((1)/(3))x^3 + ((1)/(2))x^2 where the tangent line has slope 0.
Uploaded: 2021-06-13T19:49:00-08:00
Duration: 2 min 17 s
Channel: Vikash Ranjan
Description: 7. Find all points on the graph of y = - ((1)/(3))x^3 + ((1)/(2))x^2 where the tangent line has slope 0.

          7. Find all points on the graph of $y = - \left(\frac{1}{3}\right)x^3 + \left(\frac{1}{2}\right)x^2$ where the tangent line has slope 0.

Added by Angela J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vikash Ranjan

06/13/2021

Step 1

Step 1: To find the points on the graph where the tangent line has a slope of 0, we need to find the derivative of the given function y with respect to x. Show more…

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Find all points on the graph of y=-((1)/(3))x^(3)+((1)/(2))x^(2) where the tangent line has slope 0 . 7.Find all points on the graph of y= +) 2 where the tangent line has slope 0.