00:01
Here we're given a function f of x, which is equal to 8 plus x divided by x times x minus 2.
00:10
And we're asked to find where is this continuous, discontinuous.
00:15
And then for each of those values, we want to find the limit as x approaches that value.
00:20
So let's start off by finding where is it discontinuous.
00:24
Well, it's going to be discontinuous anywhere the denominator is equal to zero.
00:28
So i'm going to get x is one of the factors.
00:31
So x equals 0 is one of the factors because i set that factor equal to 0.
00:37
I'm going to have another one because if x minus 2 is 0, the denominator is 0 as well.
00:42
So if i add 2, i'm going to get that x is equal to 2.
00:46
So i have two values that are discontinuous.
00:49
Now let's find the limit as x approaches each of those values.
00:52
So the limit as x approaches 0 of f of x.
00:57
Well, if i just blindly plug it in, i'm going to get 8 divided by 0.
01:02
That tells me the answer has to be infinite, but it doesn't tell me if it exists or not, because it could be plus or minus or both.
01:10
So now let's take a look at the left side and the right side.
01:15
So if i were to say, you know what, x is approaching zero, but x is always going to be a slightly negative number...