Find all whole number solutions of the congruence equation. (2x + 1) equiv 5 mod 4 0, 1, 2, 3, 4, 5, 6, ... 0, 4, 8, 12, 16, 20, 24, ... 0, 3, 6, 9, 12, 15, 18, ... 0, 2, 4, 6, 8, 10, 12, ... 0, 5, 10, 15, 20, 25, 30, ...
Added by Jeremy P.
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It's saying that when you take 2x + 1 and divide it by 4, the remainder is 5. However, since we are dividing by 4, the remainder can't be 5. It seems like there might be a mistake in the problem. If the congruence equation was (2x + 1) = 1 mod 4, then we could Show more…
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