00:01
In this question, we are given two cylindrical coordinates.
00:04
A is 4, 30°, 3 and b is 5, 135°, negative 5.
00:15
So we have to find the vector from point b to a.
00:25
First let's convert this into cylindrical coordinate.
00:29
So which is of the form r, theta, z.
00:39
So from this x is equals to we know that r cos theta, y is equals to r sin theta and z is going to be z.
00:50
So 3 is going to be fixed and negative 5 is going to be fixed in point a.
00:54
So let's write this as, so coordinates of a is equals to 4 times 4 cos 30° and 4 sin 30°, 3.
01:17
So 4 times of cos 30° is going to be 2 root 3 and 4 sin 30° is going to be 2 and we have 3.
01:29
So this is a coordinate.
01:31
Next we have b which is equals to 5 cos 135°.
01:42
Next we have 5 sin 135° and negative 5.
01:48
So b is going to be negative 5 over root 2 that is cos 135° is negative 1 root 2...