00:01
In this question we need to find an equation for tangent, the line tangent.
00:15
So as given here, x is equal to 9 t squared minus 6, y is equal to t squared and t is equal to 1.
00:27
So this is the given information from the question and now in the solution this question, first of all, for the equation, we will find our value for m, which is d -y -by -d -x and the point and the point of tangent, which is as x -0 and y -not.
01:06
So then we can find the equation is usually as for the usual equation, y minus y0 is equal to m x minus x note.
01:27
So when we differentiate this equation as d by d, d x upon d t is equal to d by d t, 9 t squared minus 6 which is equal to 18 t.
01:42
And now for d -y by d -t our equation will be d -t -t -t -t -stwit which is equal to two times of t and thirdly d -y by d -x which is equal to d -y by d -t divided by d -x by d -t and that is equal to 2t divided by 18 t so we will get here 1 by 9.
02:13
The value is 1 by 9, so therefore we can say this implies is m is equal to dy by d x which is equal to 1 upon 9.
02:23
So x0 comma y0 will be equal to 9 t squared minus 6 comma t squared at t is equal to 1...