Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of d^2y/dx^2 at this point. x = 4t^2 + 5, y = t^8, t = -1 Write the equation of the tangent line. y =
Added by Daniel A.
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First, we need to find the coordinates of the point on the curve where t = -1. We can do this by plugging in t = -1 into the given parametric equations for x and y: x = 4(-1)^2 + 5 = 4 + 5 = 9 y = -1 So, the point is (9, -1). Show more…
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