Find an equation of the line that is tangent to the graph of $f$ and parallel to the given line.\ Function\\Line\\$f(x) = x^3$\ $12x - y + 8 = 0$\ y =
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First, let's find the derivative of the function f(x) = x^3 - 12x - y + 8 = 0 to find the slope of the tangent line at any point on the graph of f. Show more…
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