Question

Find an equation of the plane. The plane that passes through the point (-1, 2, 2) and contains the line of intersection of the planes x + y - z = 2 and 2x - y + 3z = 3.

Name: find an equation of the plane the plane that passes through the point 1 2 2 and contains the line of intersection of the planes x y z 2 and 2x y 3z 3 41237
Uploaded: 2022-04-16T10:39:01-08:00
Duration: 1 min 47 s
Channel: Shaiju T
Description: find an equation of the plane the plane that passes through the point 1 2 2 and contains the line of intersection of the planes x y z 2 and 2x y 3z 3 41237

          Find an equation of the plane. The plane that passes through the point (-1, 2, 2) and contains the line of intersection of the planes x + y - z = 2 and 2x - y + 3z = 3.

Added by Marc G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Shaiju T

04/16/2022

Step 1

Step 1:** Find the normal vector to the required plane by taking the cross product of the normal vectors of the given planes: Normal vector of plane 1: \( \vec{n_1} = \langle 1, 1, -1 \rangle \) Normal vector of plane 2: \( \vec{n_2} = \langle 2, -1, 3 \rangle Show more…

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Find an equation of the plane. The plane that passes through the point (-1, 2, 2) and contains the line of intersection of the planes x + y - z = 2 and 2x - y + 3z = 3.