00:01
Hi, in this question, given that the plane contain the line x equals 5t and y equals 2 plus t and z equals 3 minus t.
00:14
So, this line passing through the points 0, 2, 3 and here 5, 1, minus 1.
00:30
So, here let the point, given point as 2, 3, 5 let it be a and b can be considered as 0, 2, 3 and here a and b vector are on the plane.
00:44
So, ab vector lie on the plane.
00:47
Ab vector can be written as 0 i cap plus 2 j cap plus 3 k cap minus 2 i cap plus 3 j cap plus 5 k cap which is equal to minus 2 i cap minus j cap minus 2 k cap.
01:09
Next we need to find ab vector cross 5, 1, minus 1 which is equal to i cap j cap k cap.
01:21
Ab vector is minus 2 minus 1 minus 2...