Question

Find an equation of the tangent line to the curve at the given point.\ $xy + x^2 y^2 = 12$, $(3, 1)$

Name: Find an equation of the tangent line to the curve at the given point.xy + x^2 y^2 = 12, (3, 1)
Uploaded: 2021-10-06T23:50:48-08:00
Duration: 1 min 50 s
Channel: Charles Machakwa
Description: Find an equation of the tangent line to the curve at the given point.xy + x^2 y^2 = 12, (3, 1)

          Find an equation of the tangent line to the curve at the given point.\
$xy + x^2 y^2 = 12$, $(3, 1)$

Added by Bryan S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Charles Machakwa

10/06/2021

Step 1

Taking the derivative of xy + x^2y^2 = 12 with respect to x, we get: y + 2xy^2 + 2x^2yy' = 0 Simplify this to get: y' = -y / (2xy + 2x^2y^2) Show more…

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Find an equation of the tangent line to the curve at the given point. xy+x^(2)y^(2)=12,(3,1) Find an equation of the tangent line to the curve at the given point xy+ x2y2 = 12, (3,1)