Find any intercepts. y = x^2 + 4x - 5 y-intercept: (x, y) = ( x-intercepts: (x, y) = ( (smaller x-value) (x, y) = ( (larger x-value)
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To do this, we set x = 0 and solve for y: y = (0)^2 + 4(0) - 5 y = -5 So the y-intercept is (0, -5). Now, let's find the x-intercepts. To do this, we set y = 0 and solve for x: 0 = x^2 + 4x - 5 To solve this quadratic equation, we can use the quadratic Show more…
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