Find bases for the column space, the row space, and the null space of the matrix
$$
A = \begin{bmatrix}
1 & 5 & -1 & 1 \\
3 & 18 & -1 & 6 \\
4 & 26 & 0 & 10
\end{bmatrix}
$$
You should verify that the Rank-Nullity Theorem holds.
Basis for the column space of $A = \begin{Bmatrix} \begin{bmatrix} 1 \\ 3 \\ 4 \end{bmatrix} & \begin{bmatrix} 5 \\ 18 \\ 26 \end{bmatrix} \end{Bmatrix}$
Basis for the row space of $A = \begin{Bmatrix} \begin{bmatrix} 1 & 0 & 13/3 & -4 \end{bmatrix} , \begin{bmatrix} 0 & 1 & 2/3 & 1 \end{bmatrix} \end{Bmatrix}$
Basis for the null space of $A = \begin{Bmatrix} \begin{bmatrix} \end{bmatrix} , \begin{bmatrix} \end{bmatrix} \end{Bmatrix}$
