Find dy/dx and d2y/dx2. x = t2 + 5, y = t2 + 5t dy/dx = ___ (d^2)y/d(x^2) = ______ For which values of t is the curve concave upward? (Enter your answer using interval notation.) ________
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Given x = t^2 + 5, we have: dx/dt = \frac{dx}{dt} = 2t Given y = t^2 + 5t, we have: dy/dt = \frac{dy}{dt} = 2t + 5 Now, we can find dy/dx using the chain rule: dy/dx = \frac{dy/dt}{dx/dt} = \frac{2t + 5}{2t} Show more…
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