Question

Find dy/dx by implicit differentiation. x sin(y) + y sin(x) = 2 y' = - (x cos(y) + sin(x)) / (sin(y) + y cos(x))

          Find dy/dx by implicit differentiation.
x sin(y) + y sin(x) = 2
y' = - (x cos(y) + sin(x)) / (sin(y) + y cos(x))

Added by Jacqueline W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

10/21/2023

Step 1

$\frac{d}{dx}(\sin(y) \sin(x)) = \frac{d}{dx}(2)$ Now, we apply the product rule on the left side of the equation. The product rule states that the derivative of $u(x)v(x)$ is $u'(x)v(x) + u(x)v'(x)$. In this case, $u(x) = \sin(y)$ and $v(x) = \sin(x)$. Show more…

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