Find equations of the following. z + 6 = xe^y cos(z), (6, 0, 0) (a) the tangent plane (b) the normal line (x(t), y(t), z(t)) =
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The given equation is: $$ f(x, y, z) = x e^y \cos(z) - 2 - 6 $$ Now, let's find the partial derivatives: $$ f_x = \frac{\partial f}{\partial x} = e^y \cos(z) $$ $$ f_y = \frac{\partial f}{\partial y} = x e^y \cos(z) $$ $$ f_z = \frac{\partial f}{\partial z} Show more…
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