Question

Find equations of the tangent plane and normal line to the surface x = 2y^2 + 4z^2 - 13 at the point (-5, 2, 0). Tangent Plane: make the coefficient of x equal to 1 ?=0 Normal line: (-5, ?, ?) + t(1, ?, ?)

Name: find equations of the tangent plane and normal line to the surface x 2y2 4z2 13 at the point 520 tangent plane make the coefficient of x equal to 1 0 normal line 5 t1 37574
Uploaded: 2023-07-17T16:04:18-08:00
Duration: 3 min 1 s
Channel: Adi S
Description: find equations of the tangent plane and normal line to the surface x 2y2 4z2 13 at the point 520 tangent plane make the coefficient of x equal to 1 0 normal line 5 t1 37574

          Find equations of the tangent plane and normal line to the surface x = 2y^2 + 4z^2 - 13 at the point (-5, 2, 0).
Tangent Plane: make the coefficient of x equal to 1
?=0
Normal line:
(-5, ?, ?) + t(1, ?, ?)

Added by Thomas W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

07/17/2023

Step 1

∂x/∂y = 4y ∂x/∂z = 8z Show more…

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Find equations of the tangent plane and normal line to the surface x = 2y^2 + 4z^2 - 13 at the point (-5, 2, 0). Tangent Plane: make the coefficient of x equal to 1 ?=0 Normal line: (-5, ?, ?) + t(1, ?, ?)