Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.) f''(x) = 32x^3 - 18x^2 + 10x f(x) = (8x^5)/5 - (3x^4)/2 + (5x^3)/3 + Cx + D
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The integral of 32x^3 is 8x^4, the integral of 18x^2 is 6x^3, the integral of 10x is 5x^2, the integral of 3x is 1.5x^2, and the integral of 5x is 2.5x. So, f'(x) = 8x^4 + 6x^3 + 5x^2 + 1.5x^2 + 2.5x + C. Show more…
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