The quotient rule states that if $f(t) = \frac{g(t)}{h(t)}$, then $f'(t) = \frac{g'(t)h(t) - g(t)h'(t)}{(h(t))^2}$.
In this case, $g(t) = 2t + 1$ and $h(t) = t + 3$. Therefore, $g'(t) = 2$ and $h'(t) = 1$.
Applying the quotient rule, we have:
$f'(t) = \frac{(2)(t
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