Find $f'(x)$.\newline$f(x) = \frac{e^x}{3x^2 + 8}$\newline$f'(x) = $
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f(x) = (e^x)/(3x^2 + 8) f'(x) = [(3x^2 + 8)(e^x) - (e^x)(6x)] / (3x^2 + 8)^2 f'(x) = [(3x^2 + 8)e^x - 6x(e^x)] / (3x^2 + 8)^2 Show more…
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