Find general solutions of the DEs. $$y^{(4)}+4 y^{(3)}+6 y^{\prime \prime}+4 y^{\prime}+y=0$$
Added by Brian F.
Step 1
First, we find the characteristic equation: $$r^4+4r^3+6r^2+4r+1=0$$ This can be factored as: $$(r+1)^4=0$$ So, the roots are $r=-1$ with multiplicity 4. Show more…
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