00:01
If we have the function, f of x equals 0 .2x minus 3 .1 times 1 .2x plus 4 .5, all divided by 0 .7 times the quantity x minus 0 .5 times the quantity 0 .2x plus 0 .3.
00:17
And we wanted to find the vertical and horizontal asymptotes.
00:20
If there are any.
00:22
Let's start with vertical asymptotes.
00:24
Vertical asymptotes occur at the zero of the denominator.
00:28
So let's focus on that denominator.
00:32
If x is 0 .5, or if 0 .2x plus 0 .3 was equal to 0, which is 0 .2x equals negative 0 .3, or x equals negative 0 .3 over 0 .2, which is negative 1 .5.
00:52
That's going to be your vertical asymptotes.
00:55
So first part, vertical asymptotes are going to be at x equals 0 .5.
01:05
From the first quantity, and this negative 1 .5 we just calculated.
01:19
Now, horizontal asymptotopes you analyze the degrees...