Find k so that the curve y = x^3 + kx^2 - 4x - 1 will have a relative extremum point at x = 2. k = 2 k = 4 k = -3 k = -2
Added by Nichole H.
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The derivative is y' = 1 + 2kx - 4. For a relative extremum, the derivative of the function should be equal to zero. So, we set y' = 0 and solve for x: 1 + 2kx - 4 = 0 2kx = 3 Show more…
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