Question

Find $m$ and $b$ so that the following function is differentiable everywhere. $f(x) = \begin{cases} x^2 + x + 1 & \text{if } x \le -3 \\ mx + b & \text{if } x > -3 \end{cases}$ $m = \text{_ } b = \text{_}$

          Find $m$ and $b$ so that the following function is differentiable everywhere.

$f(x) = \begin{cases} x^2 + x + 1 & \text{if } x \le -3 \\ mx + b & \text{if } x > -3 \end{cases}$

$m = \text{_____ } b = \text{_____}$

Find m and b so that the following function is differentiable everywhere.

f(x) = x^2 + x + 1 if x ≤ -3
mx + b if x > -3

m = b =

Added by David S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Deepal S

02/18/2022

Step 1

Step 1: For the function to be differentiable everywhere, it must be continuous at x = -3. Show more…

Show all steps

Thanks for your feedback!

Find m and b so that the following function is differentiable everywhere. $$f(x) = \begin{cases} x^2 + x + 1 & \text{if } x \le -3 \\ mx + b & \text{if } x > -3 \end{cases}$$ m = b =