Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = ?t^2 + 48, y = ln(t^2 + 48), z = t; (7, ln(49), 1) (x(t), y(t), z(t)) = (
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First, we need to find the derivatives of the given parametric equations with respect to t: dX/dt = 2t and dY/dt = 2t/(t^2 + 48) Show more…
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