Question

Find a parametrization of the line in which the planes x - 3y + 3z = -3 and -2x + 2y - 2z = -2 intersect. Find the parametrization of the line. Use a point with z = 0 on the line to determine the parametrization. x = , y = , z = , -? < t < ?

          Find a parametrization of the line in which the planes x - 3y + 3z = -3 and -2x + 2y - 2z = -2 intersect.
Find the parametrization of the line. Use a point with z = 0 on the line to determine the parametrization.
x = , y = , z = , -? < t < ?
        
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Find a parametrization of the line in which the planes x - 3y + 3z = -3 and -2x + 2y - 2z = -2 intersect.
Find the parametrization of the line. Use a point with z = 0 on the line to determine the parametrization.
x = , y = , z = , -? < t < ?

Added by Julian O.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Transcript

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00:01 Here consider the equations x minus 3y minus 3 is it equal to 3 and minus 2x plus 2y plus 2 is it equal to 2 which implies minus x plus y plus z equal to 1 mark this as equations 1 and 2 so from equation 1 x equal to 3 plus 3 y plus 3 is it so which is 3 times 1 plus y plus is it now put this value in equation 2.
00:34 So equation 2 becomes minus 3, minus 3 y, minus 3 is it plus y plus is it equal to 1.
00:43 So from this we can have minus 2 y minus 2 is it equal to 4.
00:48 So why plus is it equal to minus 2? from this we can have y equal to minus 2 minus z and is that equal to minus to minus y.
01:04 So now by simplifying we will get x equal to three times three plus three times minus two minus is it plus three times minus two minus y so which is equal to three minus six minus three is it minus six minus three y so which is equal to minus nine minus three y minus three is it and y equal to is that implies these two will get cancelled so we'll get this is equal to minus 9...
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