Find the absolute and local maximum and minimum values of f. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) NO PARTIAL CREDIT! f(x) = 2 + (x + 3)^2, -5 ≤ x ≤ 6 (a) Absolute Maximum (b) Absolute Minimum (c) Local Maximum (d) Local Minimum
Added by Felix R.
Step 1
f(x) = 2 + (x + 3)^2 f'(x) = 2(x + 3) Now, set f'(x) = 0: 2(x + 3) = 0 x = -3 Now, we need to check the endpoints of the interval [-5, 6] and the critical point x = -3 to find the absolute maximum and minimum values. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Carson Merrill and 93 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Tim T.
Find the absolute and local maximum and minimum values of f. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = e^4x - 4/x, 1 ≤ x ≤ 2 absolute minimum value: absolute maximum value:
Zhumagali S.
Applied Calculus Find the absolute maximum and minimum values of the function over the indicated interval, and indicate the x-values at which they occur. f(x) = 6x+5 a) [ 0 , 9] b) [ -6, 2] A) find the derivative of f F'(x) = ______ the absolute maximum value is _____ at x = _____ the absolute minimum value is ______ at x = _____ B) the absolute maximum value is ____ at x = _____ the absolute minimum value is _____ at x = ______
Ma. Theresa A.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD