Question

Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (If an answer does not exist, enter DNE.) f(x) = x^2 - 4x - 6, [0, 2] absolute maximum (x, y) = ( ) absolute minimum (x, y) = ( )

          Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (If an answer does not exist, enter DNE.)
f(x) = x^2 - 4x - 6, [0, 2]
absolute maximum (x, y) = ( )
absolute minimum (x, y) = ( )

Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (If an answer does not exist, enter DNE.)
f(x) = x^2 - 4x - 6, [0, 2]
absolute maximum (x, y) = ( )
absolute minimum (x, y) = ( )

Added by Francisco H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Kumareshwaran Rathinasabapathy

04/13/2022

Step 1

Given function: \(f(x) = x^2 - 4x - 6\) Find the derivative: \(f'(x) = 2x - 4\) Set \(f'(x) = 0\): \(2x - 4 = 0\) Solve for x: \(2x = 4\) => \(x = 2\) So, the critical point is at x = 2. ** Show more…

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