Find the absolute minimum value on [0,∞) for f(x)=(x+8)(x-4)^2 the absolute minimum_ is at x= _
Added by Josefa A.
Step 1
To find the critical points, we need to find the values of x where the derivative of f(x) is equal to zero or undefined. First, let's find the derivative of f(x): f'(x) = (x-4)^2 + (x+8)(2)(x-4) Next, let's set the derivative equal to zero and solve for Show more…
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