00:01
In this problem, find the area under the given curve over the indicated interval, right? so here are two problems given to us.
00:11
So here, pi is equal to x cube here for closed interval 2 to 3 here.
00:19
Is it? so now what we are asked to find the area, right? so here we can write this is nothing but we will just integrate it.
00:30
So area will be integration of y, right? we will just integrate on the board side.
00:43
So we will get here from this, this x cubed, right? x cubed dx you can say.
00:50
So here the limits will be 2 to 3 simply.
00:53
So we will get here, y equals to, so you can write here in this way.
01:07
This is area only right so area will be equals to x to the power 4 by right so this will be 2 to 3 right so we will get here 3 to the power 4 right and this is 1 by 4 is taken common so 3 to the power 4 minus 16 divided by 4.
01:48
So this will give us area as 16 .2 square unit, right? right.
02:02
So here unit is not given.
02:04
That's why we have been given the square unit because the area must be in squares.
02:13
So this is for the first problem...