Find the area of the part of the surface z = x 2 + y that lies above the triangle with vertices (0, 0), (1, 0) and (1, 3).
Added by Pedro G.
Step 1
The equation of the line passing through two points (x1, y1) and (x2, y2) is given by: y - y1 = (y2 - y1)/(x2 - x1) * (x - x1) Substitute (0, 0) and (1, 3) into the equation: y - 0 = (3 - 0)/(1 - 0) * (x - 0) y = 3x Show more…
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