Question

Find the area of the region bounded by the graph of the polar equation that lies in the specified sector. r = e^{-?/12}, ?/2 ? ? ? ? Step 1 Recall the formula for a region whose boundary is given by a polar curve r = f(?) and by the rays ? = a and ? = b. A = ?_a^b 1/2 r^2 d? We are given the area bounded by the graph of the polar equation r = e^{-?/12} that lies in the sector ?/2 ? ? ? ?. Therefore, the area of the region bounded by the given polar equation is as follows. A = ?_{?/2}^? ( ) d?

          Find the area of the region bounded by the graph of the polar equation that lies in the specified sector.
r = e^{-?/12}, ?/2 ? ? ? ?

Step 1
Recall the formula for a region whose boundary is given by a polar curve r = f(?) and by the rays ? = a and ? = b.
A = ?_a^b 1/2 r^2 d?

We are given the area bounded by the graph of the polar equation r = e^{-?/12} that lies in the sector ?/2 ? ? ? ?.
Therefore, the area of the region bounded by the given polar equation is as follows.
A = ?_{?/2}^? ( ) d?

Find the area of the region bounded by the graph of the polar equation that lies in the specified sector.
r = e^-?/12, ?/2 ? ? ? ?

Step 1
Recall the formula for a region whose boundary is given by a polar curve r = f(?) and by the rays ? = a and ? = b.
A = ?a^b 1/2 r^2 d?

We are given the area bounded by the graph of the polar equation r = e^-?/12 that lies in the sector ?/2 ? ? ? ?.
Therefore, the area of the region bounded by the given polar equation is as follows.
A = ??/2^? ( ) d?

Added by Cory N.

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