Question

Find the area of the region described. The region bounded by $y = \frac{16}{4 + x^2}$ and $y = 1$ The area of the region is $oxed{}$ (Type an exact answer.)

          Find the area of the region described.
The region bounded by $y = \frac{16}{4 + x^2}$ and $y = 1$
The area of the region is $oxed{}$ (Type an exact answer.)

Find the area of the region described.
The region bounded by y = (16)/(4 + x^2) and y = 1
The area of the region is oxed (Type an exact answer.)

Added by Javier D.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

08/02/2023

Step 1

$$ \frac{16}{4+x^2} = 1 $$ $$ 16 = 4 + x^2 $$ $$ x^2 = 12 $$ $$ x = \pm 2\sqrt{3} $$ Show more…

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Find the area of the region described. The region bounded by y = $$ \frac{16}{4+x^2} $$ and y = 1 The area of the region is [ ] (Type an exact answer.)