Find the area of the shaded region bounded by $y = 6x$ and $y = x\sqrt{(14^2 - x^2)}.$
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To find the points of intersection, set the two equations equal to each other: 6x = x√(14^2-x^2) Solve for x: 6 = √(14^2-x^2) 36 = 14^2 - x^2 x^2 = 14^2 - 36 x^2 = 196 - 36 x^2 = 160 x = ±√160 x = ±4√10 So the points of intersection are at x = -4√10 and x = Show more…
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