Find the area of the surface generated when the given curve is revolved about the given axis. y = 6x + 5, for 0 ? x ? 6; about the x-axis The surface area is square units. (Type an exact answer in terms of ?.)
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Step 1: Calculate the integral of \(6x + 5\) squared: \[ \int (6x + 5)^2 \, dx = \int (36x^2 + 60x + 25) \, dx = 12x^3 + 30x^2 + 25x + C \] Show more…
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