Question

Find the area of the surface generated when the given curve is revolved about the given axis.\ y = 9x - 6, for $1 \le x \le 2$; about the y-axis (Hint: Integrate with respect to y.)

Name: Find the area of the surface generated when the given curve is revolved about the given axis.y = 9x - 6, for 1 ≤ x ≤ 2; about the y-axis (Hint: Integrate with respect to y.)
Uploaded: 2023-06-28T06:49:07-08:00
Duration: 3 min 13 s
Channel: Madhur L
Description: Find the area of the surface generated when the given curve is revolved about the given axis.y = 9x - 6, for 1 ≤ x ≤ 2; about the y-axis (Hint: Integrate with respect to y.)

          Find the area of the surface generated when the given curve is revolved about the given axis.\
y = 9x - 6, for $1 \le x \le 2$; about the y-axis (Hint: Integrate with respect to y.)

Find the area of the surface generated when the given curve is revolved about the given axis.y = 9x - 6, for 1 ≤ x ≤ 2; about the y-axis (Hint: Integrate with respect to y.)

Added by Louis G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

06/28/2023

Step 1

We can do this by rearranging the given equation: y = 9x - 6 9x = y + 6 x = (y + 6)/9 Show more…

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Find the area of the surface generated when the given curve is revolved about the given axis. y=9x-6, for 1<=x<=2; about the y-axis (Hint: Integrate with respect to y.) Find the area of the surface generated when the given curve is revolved about the given axis. y=9x-6, for 1<=x<=2; about the y-axis. Hint: Integrate with respect to y.