2. Find the area of the surface of revolution obtained by revolving the given curve about the $y$-axis. $y = \frac{x^2}{4} - \frac{\ln(x)}{2}$, $1 \le x \le 2$ $\frac{19}{3}\pi$ $\frac{17}{3}\pi$ $2\pi$ $\frac{2}{3}\pi$ $\frac{10}{3}\pi$

          2. Find the area of the surface of revolution obtained by revolving the given curve about the $y$-axis.
$y = \frac{x^2}{4} - \frac{\ln(x)}{2}$, $1 \le x \le 2$
$\frac{19}{3}\pi$
$\frac{17}{3}\pi$
$2\pi$
$\frac{2}{3}\pi$
$\frac{10}{3}\pi$

2. Find the area of the surface of revolution obtained by revolving the given curve about the y-axis.
y = (x^2)/(4) - (ln(x))/(2), 1 ≤ x ≤ 2
(19)/(3)π
(17)/(3)π
2π
(2)/(3)π
(10)/(3)π

Added by Margaret R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

07/27/2023

Step 1

The given curve is y=(x^(2))/(4)-(ln(x))/(2), 1<=x<=2. Show more…

Show all steps

Thanks for your feedback!

Find the area of the surface of revolution obtained by revolving the given curve about the y-axis. y=(x^(2))/(4)-(ln(x))/(2),1<=x<=2 (19)/(3)pi (17)/(3)pi 2pi (2)/(3)pi (10)/(3)pi 2.Find the area of the surface of revolution obtained by revolving the given curve about the y-axis A 19 3 17 3 TT 2T 2 TT 10 3TT