Find the axis of symmetry of the given function. $f(x) = x^2 - 3x + 4$ A. $x = \frac{3}{4}$ B. $x = -\frac{3}{2}$ C. $x = 3$ D. $x = \frac{3}{2}$
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A quadratic function is generally given in the form $f(x) = ax^2 + bx + c$. For the given function, $f(x) = x^2 - 3x + 4$, we can identify the coefficients: $a = 1$ $b = -3$ $c = 4$ Show more…
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