Question

Find the center, radius, and intercepts of the circle with the given equation and then sketch the graph. $x^2 + y^2 - 16x + 4y + 52 = 0$

          Find the center, radius, and intercepts of the circle with the given equation and then sketch the graph.
$x^2 + y^2 - 16x + 4y + 52 = 0$
        
Find the center, radius, and intercepts of the circle with the given equation and then sketch the graph.
x^2 + y^2 - 16x + 4y + 52 = 0

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Find the center, radius, and intercepts of the circle with the given equation and then sketch the graph. x^(2)+y^(2)-16x+4y+52=0 Find the center, radius, and intercepts of the circle with the given equation and then sketch the graph. 2+y2-16x+4y+52=0
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Transcript

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00:01 Okay, here i want to work out the center and radius of this circle.
00:06 Well, the circle formula in general is x minus a squared plus y minus b squared equals r squared.
00:17 That's called standard form.
00:20 And this means ab is your center and r is your radius.
00:30 So here then what we have, the a i can see is minus two thirds.
00:38 So my center here is going to be minus two thirds and b is one half.
00:52 So negative two thirds and one half is my circle center.
00:57 And the radius i can see is the square root of eight over nine.
01:06 In the words, this here is r squared.
01:08 And that i can write as root 8 over 3 or as 2 root 2 over 3.
01:20 So there is my circle center and there is my radius 2 root 2 over 3 or root 8 over 3 would be fine.
01:34 Now then i want to draw this circle.
01:38 So you have the axes x and y and center first.
01:44 Minus two thirds and one half...
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