Question

Find the centroid ($\bar{x}$, $\bar{y}$) of the region bounded by: $y = 9x^2 + 9x$, $y = 0$, $x = 0$, and $x = 3$ $\bar{x} = $ $\bar{y} = $

          Find the centroid ($\bar{x}$, $\bar{y}$) of the region bounded by:
$y = 9x^2 + 9x$, $y = 0$, $x = 0$, and $x = 3$
$\bar{x} = $
$\bar{y} = $

Find the centroid (x̅, y̅) of the region bounded by:
y = 9x^2 + 9x, y = 0, x = 0, and x = 3
x̅ =
y̅ =

Added by Enrique M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Lucas Finney

12/17/2021

Step 1

To find the area, we need to integrate the difference between the upper and lower curves with respect to x over the interval [0,3]. Area = ∫[0,3] (9x^2 + 9x - 0) dx Area = ∫[0,3] (9x^2 + 9x) dx Area = [3x^3/3 + 9x^2/2] evaluated from 0 to 3 Area = [3(3)^3/3 + Show more…

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Find the centroid (ar{x} (,)/(b)ar (y)) of the region bounded by: y=9x^(2)+9x,y=0,x=0, and x=3 ar{x} =()/(b) ar (y)= Find the centroid (,y) of the region bounded by: y=9x+9x y=0,x=0 andx3 =c y=