00:01
In this question, there are given two clauses.
00:03
So in the first part, the clause is between 4 .3 and 47.
00:09
So what we have to do, we have to find the clause boundaries.
00:13
So for class boundaries, what we have to do, first of all, we don't know the next step here.
00:22
So i'm going to just subtract 0 .5 from each boundaries.
00:27
So for the lower boundary, we have for the 3 and minus 0 .5, which is.
00:32
Is 42 .5 and 4 .7, and i'm going to add 4 to7, 0 .5, and which is equal to 47 .5.
00:42
So the boundaries are 42 .5 and 47 .5.
00:48
These are the class boundaries.
00:50
What about the midpoint? so the midpoint, so basically i can just add those two numbers, so i can add 43 and 47, and divide these numbers by two.
01:02
I will get the midpoint, which is 45.
01:05
So this is the midpoint for this class.
01:08
And what about the lost part? so the width of this class, i'm going to just subtract the class boundaries from upper to lower.
01:17
So the upper one for the 7 .5 and the lower one is 42 .5.
01:22
If i subtract between them, i will get five.
01:24
So this is the width of this glass here.
01:27
And what about for the next one? so for the next one, we have 8 .24 and 18 .5.
01:36
So in this case, what we have to do, we have to just subtract, we have to subtract 0 .05 here.
01:44
So for the klaus boundary, klaus boundaries, so there's an hundredth here.
01:51
So i'm going to subtract 0 .05, which is 8 .24 and minus, this is 0 .05, which is, let me just do here...