Find the component form of the vector $\mathbf{v}$ where $|\mathbf{v}| = 30$ and $\theta = 28^\circ$. Round your answers to two decimal places. Note: The picture may not be to scale.
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We are given that $|\mathbf{v}| = 30$ and $\theta = 28^\circ$. The magnitude of $\mathbf{v}$ is given by $|\mathbf{v}| = \sqrt{x^2 + y^2} = 30$. The angle $\theta$ is given by $\tan \theta = \frac{y}{x}$. We have $\tan 28^\circ = \frac{y}{x}$. Therefore, $y = x Show more…
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