00:01
So for this problem, we are told to find the components of the total velocity vector along the s and y axis that is shown in the following figure.
00:11
This one right here, where the angle theta, we are given its value and that is equal to 20 degrees.
00:22
And the magnitude of this total speed is 6 .08 meters per second.
00:32
Now, as you can see in here, the total angle that this vector meets with the horizontal, with the x -atxis, we're going to call that angle that angle beta, and that will be just simply the angle theta that we are given, plus the angle that is shown in here that is 26 .5 degrees.
00:53
So the total angle when we substitute the angle theta in here, which is 20 degrees, is going to be 46 .5 degrees.
01:02
So with that said, the x component of this total speed is just simply the magnitude of the vector that we are given 6 .08 meters per second.
01:14
That times the cosine of the angle, so that will be the cosine of 406 .5 degrees...